11(k-2)+[k-3(k+1)]=0

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Solution for 11(k-2)+[k-3(k+1)]=0 equation:


Simplifying
11(k + -2) + [k + -3(k + 1)] = 0

Reorder the terms:
11(-2 + k) + [k + -3(k + 1)] = 0
(-2 * 11 + k * 11) + [k + -3(k + 1)] = 0
(-22 + 11k) + [k + -3(k + 1)] = 0

Reorder the terms:
-22 + 11k + [k + -3(1 + k)] = 0
-22 + 11k + [k + (1 * -3 + k * -3)] = 0
-22 + 11k + [k + (-3 + -3k)] = 0

Reorder the terms:
-22 + 11k + [-3 + k + -3k] = 0

Combine like terms: k + -3k = -2k
-22 + 11k + [-3 + -2k] = 0

Remove brackets around [-3 + -2k]
-22 + 11k + -3 + -2k = 0

Reorder the terms:
-22 + -3 + 11k + -2k = 0

Combine like terms: -22 + -3 = -25
-25 + 11k + -2k = 0

Combine like terms: 11k + -2k = 9k
-25 + 9k = 0

Solving
-25 + 9k = 0

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '25' to each side of the equation.
-25 + 25 + 9k = 0 + 25

Combine like terms: -25 + 25 = 0
0 + 9k = 0 + 25
9k = 0 + 25

Combine like terms: 0 + 25 = 25
9k = 25

Divide each side by '9'.
k = 2.777777778

Simplifying
k = 2.777777778

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